A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813× 10-4 The mass of the particle is (me=9.1×10-31 kg)

Question

A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813× 10-4 The mass of the particle is (me=9.1×10-31 kg) (A) 1.67 × 10-27 kg (B) 1.67 × 10-31 kg (C) 1.67 × 10-19 kg (D) 1.67 × 10-14 kg

Tardigrade Admin · Accepted Answer

de Broglie wavelength of a moving particle having mass m and velocity v is given by λ=(h/p)=(h/mv) or m=(h/λ v) For an electron λe=(h/me ve) or me =(h/λe ve) Given: (v/ve)=3 and (λ/λe)=1.813×10-4 Mass of the particle, m=me ((λe/λ))((v0/v)) Substituting the values, we get m=9.1×10-31×(1/1.813×10-4)×(1/3) or m=1.67×10-27kg

Q. A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is $1.813 \times 1 0^{- 4}$ The mass of the particle is $(m_{e} = 9.1 \times 1 0^{- 31} k g)$

$1.67 \times 1 0^{- 27} k g$

$1.67 \times 1 0^{- 31} k g$

$1.67 \times 1 0^{- 19} k g$

$1.67 \times 1 0^{- 14} k g$

Q. A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is 1.813×10−4 The mass of the particle is (me​=9.1×10−31kg)

1.67×10−27kg

1.67×10−31kg

1.67×10−19kg

1.67×10−14kg

Q. A particle is moving three times as fast as an electron. The ratio of the de Broglie wavelength of the particle to that of the electron is $1.813 \times 1 0^{- 4}$ The mass of the particle is $(m_{e} = 9.1 \times 1 0^{- 31} k g)$

$1.67 \times 1 0^{- 27} k g$

$1.67 \times 1 0^{- 31} k g$

$1.67 \times 1 0^{- 19} k g$

$1.67 \times 1 0^{- 14} k g$