A particle is moving on a circular path with constant speed v. It moves between two points A and B, which subtends an angle 60° at the centre of circle. The magnitude of change in its velocity and change in magnitude of its velocity during motion from A to B are respectively

Question

A particle is moving on a circular path with constant speed v. It moves between two points A and B, which subtends an angle 60° at the centre of circle. The magnitude of change in its velocity and change in magnitude of its velocity during motion from A to B are respectively (A) Zero, Zero (B) v , 0 (C) 0, v (D) 2 v , v

Tardigrade Admin · Accepted Answer

Δ v =2 v sin (θ/2) 2 v × sin ((60/2)) | Δ v| = v Change in magnitude of velocity = 0

Q. A particle is moving on a circular path with constant speed $v$ . It moves between two points $A$ and $B$ , which subtends an angle $6 0^{\circ}$ at the centre of circle. The magnitude of change in its velocity and change in magnitude of its velocity during motion from $A$ to $B$ are respectively

Zero, Zero

v , 0

0, v

2 v , v

$Δ v = 2 v sin \frac{θ}{2}$
$2 v \times sin (\frac{60}{2})$
$∣Δ v ∣ = v$
Change in magnitude of velocity $= 0$

Q. A particle is moving on a circular path with constant speed v. It moves between two points A and B, which subtends an angle 60∘ at the centre of circle. The magnitude of change in its velocity and change in magnitude of its velocity during motion from A to B are respectively

Zero, Zero

v , 0

0, v

2 v , v

Δv=2vsin2θ​ 2v×sin(260​) ∣Δv∣=v Change in magnitude of velocity =0

$Δ v = 2 v sin \frac{θ}{2}$
$2 v \times sin (\frac{60}{2})$
$∣Δ v ∣ = v$
Change in magnitude of velocity $= 0$