A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angle 30° and 60° from vertical (lowest position) are T1 and T2 respectively, then

Question

A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angle 30° and 60° from vertical (lowest position) are T1 and T2 respectively, then (A) T1=T2 (B) T2>T1 (C) T1>T2 (D) tension in the string always remains the same

Tardigrade Admin · Accepted Answer

Tension, T=(m v2/r)+m g cos θ For, θ=30°, T1=(m v2/r)+m g cos 30° θ=60°, T2=(m v2/r)+m g cos 60° ∴ T1 >T2

Q. A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angle $3 0^{\circ}$ and $6 0^{\circ}$ from vertical (lowest position) are $T_{1}$ and $T_{2}$ respectively, then

$T_{1} = T_{2}$

$T_{2} > T_{1}$

$T_{1} > T_{2}$

tension in the string always remains the same

Tension, $T = \frac{m v ^{2}}{r} + m g cos θ$
For, $θ = 3 0^{\circ},$
$T_{1} = \frac{m v ^{2}}{r} + m g cos 3 0^{\circ}$
$θ = 6 0^{\circ}, T_{2} = \frac{m v ^{2}}{r} + m g cos 6 0^{\circ}$
$∴ T_{1} > T_{2}$

Q. A particle is moving in a vertical circle. The tensions in the string when passing through two positions at angle 30∘ and 60∘ from vertical (lowest position) are T1​ and T2​ respectively, then

T1​=T2​

T2​>T1​

T1​>T2​