A particle is moving in a straight line such that its velocity is increasing at 5 ms -1 per meter. The acceleration of the particle is ms -2 at a point where its velocity is 20 ms -1.

Question

A particle is moving in a straight line such that its velocity is increasing at 5 ms -1 per meter. The acceleration of the particle is ms -2 at a point where its velocity is 20 ms -1. (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

(d v/d s)=5 a=v (d v/d s)=20 × 5=100 m / sec 2

Q. A particle is moving in a straight line such that its velocity is increasing at $5 m s^{- 1}$ per meter. The acceleration of the particle is _____ $m s^{- 2}$ at a point where its velocity is $20 m s^{- 1}$ .

$\frac{d v}{d s} = 5$
$a = v \frac{d v}{d s} = 20 \times 5 = 100 m / se c^{2}$

Q. A particle is moving in a straight line such that its velocity is increasing at 5ms−1 per meter. The acceleration of the particle is _____ms−2 at a point where its velocity is 20ms−1.

dsdv​=5 a=vdsdv​=20×5=100m/sec2

Q. A particle is moving in a straight line such that its velocity is increasing at $5 m s^{- 1}$ per meter. The acceleration of the particle is _____ $m s^{- 2}$ at a point where its velocity is $20 m s^{- 1}$ .

$\frac{d v}{d s} = 5$
$a = v \frac{d v}{d s} = 20 \times 5 = 100 m / se c^{2}$