A particle is moving in a circle with uniform speed v . In moving from a point to another diametrically opposite point,

Question

A particle is moving in a circle with uniform speed v . In moving from a point to another diametrically opposite point, (A) the momentum changes by mv  (B) the momentum changes by 2 mv  (C) the kinetic energy changes by (1/2) mv2  (D) the kinetic energy changes by mv2

Tardigrade Admin · Accepted Answer

Initial velocity v1=v Final velocity v2=- v. Initial momentum p1=mv Final momentum p2=m (-v)=- mv Change in momentum Δ p=p1-p2 =mv-(-mv) =2 mv

Q. A particle is moving in a circle with uniform speed $v$ . In moving from a point to another diametrically opposite point,

the momentum changes by $m v$

the momentum changes by 2 $m v$

the kinetic energy changes by (1/2) $m v^{2}$

the kinetic energy changes by $m v^{2}$

Initial velocity
$v_{1} = v$ Final velocity $v_{2} = - v .$ Initial momentum $p_{1} = m v$ Final momentum $p_{2} = m (- v) = - m v$ Change in momentum $Δ p = p_{1} - p_{2}$ $= m v - (- m v)$ $= 2 m v$

Q. A particle is moving in a circle with uniform speed v . In moving from a point to another diametrically opposite point,

the momentum changes by mv

the momentum changes by 2 mv

the kinetic energy changes by (1/2) mv2

the kinetic energy changes by mv2