A particle is moving in a circle of radius 1 cm and with a constant speed of 8 cm s- 1 . Centre of the circle lies on principal axis of a converging lens of focal length 50 cm and at a distance of 75 cm from the lens. Plane of the circle is perpendicular to principal axis,. The correct statement is

Question

A particle is moving in a circle of radius 1 cm and with a constant speed of 8 cm s- 1 . Centre of the circle lies on principal axis of a converging lens of focal length 50 cm and at a distance of 75 cm from the lens. Plane of the circle is perpendicular to principal axis,. The correct statement is (A) Speed of the image is 4cms- 1 (B) Speed of the image is 8cms- 1 (C) Speed of the image is 16cms- 1 (D) Speed of the image is 3.2cms- 1

Tardigrade Admin · Accepted Answer

m=(f/f + u)=-2 ⇒ radius of image = 2cm ∵ ω is same ⇒ (8/1)=(v/2)⇒ v=16 cms- 1 .

Speed of the image is $4 c m s^{- 1}$

Speed of the image is $8 c m s^{- 1}$

Speed of the image is $16 c m s^{- 1}$

Speed of the image is $3.2 c m s^{- 1}$

$m = \frac{f}{f + u} = - 2$
$\Rightarrow$ radius of image = $2 c m$
$∵ ω$ is same
$\Rightarrow \frac{8}{1} = \frac{v}{2} \Rightarrow v = 16 c m s^{- 1}$ .

Q. A particle is moving in a circle of radius 1cm and with a constant speed of 8cms−1 . Centre of the circle lies on principal axis of a converging lens of focal length 50cm and at a distance of 75cm from the lens. Plane of the circle is perpendicular to principal axis,. The correct statement is

Speed of the image is 4cms−1

Speed of the image is 8cms−1

Speed of the image is 16cms−1

Speed of the image is 3.2cms−1

m=f+uf​=−2 ⇒ radius of image = 2cm ∵ω is same ⇒18​=2v​⇒v=16cms−1 .

Speed of the image is $4 c m s^{- 1}$

Speed of the image is $8 c m s^{- 1}$

Speed of the image is $16 c m s^{- 1}$

Speed of the image is $3.2 c m s^{- 1}$

$m = \frac{f}{f + u} = - 2$
$\Rightarrow$ radius of image = $2 c m$
$∵ ω$ is same
$\Rightarrow \frac{8}{1} = \frac{v}{2} \Rightarrow v = 16 c m s^{- 1}$ .