Question

A particle is executing the motion $x=a\cos (\omega t-\theta ).$ The maximum velocity of the particle is :

• A. $a\omega \cos \theta$
• B. $a\omega$
• C. $a\omega \sin \theta$
• D. none of these

Answer 1

Answer: (B)

Given equation is $x=a\cos (\omega t-\theta )$ So, velocity $\left|\frac{dx}{dt}\right|=a\omega \sin (\omega t-\theta )$ At $(\omega t-\theta )=90{}^{\circ },$ the velocity will be maximum, therefore the maximum velocity is $\upsilon =a\omega$