Question

A particle is executing the motion $ x=a\,\cos (\omega t-\theta ). $ The maximum velocity of the particle is :

• A. $ a\,\omega \,\cos \theta $
• B. $ a\,\omega \, $
• C. $ a\,\omega \,\sin \theta $
• D. none of these

Answer 1

Answer: (B)

Given equation is $ x=a\cos (\omega t-\theta ) $ So, velocity $ \left| \frac{dx}{dt} \right|=a\omega \sin (\omega t-\theta ) $ At $ (\omega t-\theta )=90{}^\circ , $ the velocity will be maximum, therefore the maximum velocity is $ \upsilon =a\omega $