Question

A particle is executing the motion $x=a\cos (\omega t-\theta ).$ The velocity of the particle is:

• A. $a\omega \cos \theta$
• B. $a\omega$
• C. $a\omega \sin \theta$
• D. none of these

Answer 1

Answer: (B)

Given equation is $x=a\cos (\omega t-\theta )$
So, velocity $\left|\frac{dx}{dt}\right|=a\omega \sin (\omega t-\theta )$
At $(\omega t-\theta )=90^{\circ }$,
the velocity will be maximum,
therefore the maximum velocity is
$v=\alpha \omega$