A particle is dropped from a tower in a uniform gravitational field at t = 0. The particle is blown over by horizontal wind with constant velocity. Slope of trajectory of particle (tan θ) with horizontal varies according to

Question

A particle is dropped from a tower in a uniform gravitational field at t = 0. The particle is blown over by horizontal wind with constant velocity. Slope of trajectory of particle (tan θ) with horizontal varies according to (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

Let v be the horizontal speed provided by wind then at any instant t tan θ=(g t/v) also X=v t so, tan θ=(g X/v2) <img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/5e3def6e53d168e441a2638538071ee7-.png" />

Q. A particle is dropped from a tower in a uniform gravitational field at $t = 0$ . The particle is blown over by horizontal wind with constant velocity. Slope of trajectory of particle $(t an θ)$ with horizontal varies according to

Let v be the horizontal speed provided by wind then at any instant $t$
$tan θ = \frac{g t}{v}$ also $X = v t$
so, $tan θ = \frac{g X}{v ^{2}}$

Q. A particle is dropped from a tower in a uniform gravitational field at t=0. The particle is blown over by horizontal wind with constant velocity. Slope of trajectory of particle (tanθ) with horizontal varies according to

Let v be the horizontal speed provided by wind then at any instant t tanθ=vgt​ also X=vt so, tanθ=v2gX​

Q. A particle is dropped from a tower in a uniform gravitational field at $t = 0$ . The particle is blown over by horizontal wind with constant velocity. Slope of trajectory of particle $(t an θ)$ with horizontal varies according to

Let v be the horizontal speed provided by wind then at any instant $t$
$tan θ = \frac{g t}{v}$ also $X = v t$
so, $tan θ = \frac{g X}{v ^{2}}$