A particle is dropped from a height H. The de-Broglie wavelength of the particle as a function of height is proportional to

Question

A particle is dropped from a height H. The de-Broglie wavelength of the particle as a function of height is proportional to (A) H (B) H1 / 2 (C) H0 (D) H-1 / 2

Tardigrade Admin · Accepted Answer

Velocity acquired by a particle while falling from a height H is, v=√2 gH λ=(h/m v)=(h/m √2 g H) text or λ propto H-(1/2)

Q. A particle is dropped from a height $H$ . The de-Broglie wavelength of the particle as a function of height is proportional to

$H$

$H^{1/2}$

$H^{0}$

$H^{- 1/2}$

Velocity acquired by a particle while falling from a height $H$ is, $v = 2 g H$
$λ = \frac{h}{m v} = \frac{h}{m 2 g H} or λ \propto H^{- \frac{1}{2}}$

Q. A particle is dropped from a height H. The de-Broglie wavelength of the particle as a function of height is proportional to

H

H1/2

H0

H−1/2

Velocity acquired by a particle while falling from a height H is, v=2gH​ λ=mvh​=m2gH​h​ or λ∝H−21​

Q. A particle is dropped from a height $H$ . The de-Broglie wavelength of the particle as a function of height is proportional to

$H$

$H^{1/2}$

$H^{0}$

$H^{- 1/2}$

Velocity acquired by a particle while falling from a height $H$ is, $v = 2 g H$
$λ = \frac{h}{m v} = \frac{h}{m 2 g H} or λ \propto H^{- \frac{1}{2}}$