A particle having charge q and mass m is projected with velocity vecv = 2 hati - 3 hatj in a uniform electric field vecE = E0 . hatj. Change in momentum | Δ barp | during any time interval t is given by :

Question

A particle having charge q and mass m is projected with velocity vecv = 2 hati - 3 hatj in a uniform electric field vecE = E0 . hatj. Change in momentum | Δ barp | during any time interval t is given by : (A) √qE0 t (B) q E0 t (C) (q E0 t/m) (D) zero

Tardigrade Admin · Accepted Answer

Impulse = mv - mu = Change in momentum = force × time qE0 × t = qE0t = Change in momentum

Q. A particle having charge q and mass m is projected with velocity $v = 2 \hat{i} - 3 \hat{j}$ in a uniform electric field $E = E_{0} . \hat{j}$ . Change in momentum $∣Δ \overset{p}{ˉ} ∣$ during any time interval t is given by :

$q E_{0} t$

$q E_{0} t$

$\frac{q E _{0} t}{m}$

zero

Impulse = mv - mu = Change in momentum
= force $\times$ time $q E_{0} \times t = q E_{0} t$
= Change in momentum

Q. A particle having charge q and mass m is projected with velocity v=2i^−3j^​ in a uniform electric field E=E0​.j^​. Change in momentum ∣Δpˉ​∣ during any time interval t is given by :

qE0​t​

qE0​t

mqE0​t​

zero

Impulse = mv - mu = Change in momentum = force × time qE0​×t=qE0​t = Change in momentum

Q. A particle having charge q and mass m is projected with velocity $v = 2 \hat{i} - 3 \hat{j}$ in a uniform electric field $E = E_{0} . \hat{j}$ . Change in momentum $∣Δ \overset{p}{ˉ} ∣$ during any time interval t is given by :

$q E_{0} t$

$q E_{0} t$

$\frac{q E _{0} t}{m}$

Impulse = mv - mu = Change in momentum
= force $\times$ time $q E_{0} \times t = q E_{0} t$
= Change in momentum