A particle having charge q and mass m is projected with velocity vecv=2 hati-3 hatj in uniform electric field vecE=E0 ⋅ hatj. Change in momentum |Δ vecp| during any time interval t is given by:

Question

A particle having charge q and mass m is projected with velocity vecv=2 hati-3 hatj in uniform electric field vecE=E0 ⋅ hatj. Change in momentum |Δ vecp| during any time interval t is given by: (A) √13 M (B) q E0 t (C) (q E0 t/m) (D) zero

Tardigrade Admin · Accepted Answer

The product of force and time interval is called impulse. Also from Newton's second law, we have

F = m a = m \frac{Δ v}{Δ t}

F \cdot Δ t = m Δ v = Δ p

The force on charge

q

due to electric field is

q E_{0}

∴ Impulse = q E_{0} t .

Q. A particle having charge $q$ and mass $m$ is projected with velocity $v = 2 \hat{i} - 3 \hat{j}$ in uniform electric field $E = E_{0} \cdot \hat{j}$ . Change in momentum $∣Δ p ∣$ during any time interval $t$ is given by:

$13 M$

$q E_{0} t$

$\frac{q E _{0} t}{m}$

zero

The product of force and time interval is called impulse. Also from Newton's second law, we have
$F = m a = m \frac{Δ v}{Δ t}$
$F \cdot Δ t = m Δ v = Δ p$
The force on charge $q$ due to electric field is $q E_{0}$
$∴ Impulse = q E_{0} t .$

Q. A particle having charge q and mass m is projected with velocity v=2i^−3j^​ in uniform electric field E=E0​⋅j^​. Change in momentum ∣Δp​∣ during any time interval t is given by:

13​M

qE0​t

mqE0​t​