A particle having a mass 0.5 kg is projected under gravity with a speed of 98 m/sec at an angle of 60°. The magnitude of the change in momentum (in N-sec) of the particle after 10 seconds is [g = 9.8 m/sec2]

Question

A particle having a mass 0.5 kg is projected under gravity with a speed of 98 m/sec at an angle of 60°. The magnitude of the change in momentum (in N-sec) of the particle after 10 seconds is [g = 9.8 m/sec2] (A) 0.5 (B) 49 (C) 98 (D) 490

Tardigrade Admin · Accepted Answer

Change in momentum F× t =mg×10 ⇒ 0.5×9.8×10 ⇒ 49 N-sec

Q. A particle having a mass $0.5 k g$ is projected under gravity with a speed of $98 m / sec$ at an angle of $6 0^{\circ}$ . The magnitude of the change in momentum (in N-sec) of the particle after 10 seconds is $[g = 9.8 m / se c^{2}]$

$0.5$

$49$

$98$

$490$

Change in momentum $F \times t$
$= m g \times 10$
$\Rightarrow 0.5 \times 9.8 \times 10$
$\Rightarrow 49 N - sec$

Q. A particle having a mass 0.5kg is projected under gravity with a speed of 98m/sec at an angle of 60∘. The magnitude of the change in momentum (in N-sec) of the particle after 10 seconds is [g=9.8m/sec2]

0.5

49

98

490