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Q. A particle having a mass $0.5\, kg$ is projected under gravity with a speed of $98\, m/sec$ at an angle of $60^\circ$. The magnitude of the change in momentum (in N-sec) of the particle after 10 seconds is $[g = 9.8\, m/sec^2]$

VITEEEVITEEE 2019

Solution:

Change in momentum $F\times t$
$=mg\times10$
$\Rightarrow 0.5\times9.8\times10$
$\Rightarrow 49\,N-sec$