A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s1 in the first 10 seconds and distance s2 in the next 10 seconds, then

Question

A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s1 in the first 10 seconds and distance s2 in the next 10 seconds, then (A) s2 = s1 (B) s2 = 2 s1 (C) s2 = 3 s1 (D) s2 = 4 s1

Tardigrade Admin · Accepted Answer

Let a be the constant acceleration of the particle. Then s = ut + (1/2) at2 or s1 = 0 + (1/2) × a × (10)2 = 50 a and s2 = [ 0 + (1/2) a (20)2] - 50a = 150 a ∴ s2 = 3s1

Q. A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance $s_{1}$ in the first 10 seconds and distance $s_{2}$ in the next 10 seconds, then

$s_{2}$ = $s_{1}$

$s_{2}$ = $2 s_{1}$

$s_{2}$ = $3 s_{1}$

$s_{2}$ = $4 s_{1}$

Let a be the constant acceleration of the particle.
Then $s = u t + \frac{1}{2} a t^{2}$
or $s_{1} = 0 + \frac{1}{2} \times a \times (10)^{2} = 50 a$
and $s_{2} = [0 + \frac{1}{2} a (20)^{2}] - 50 a = 150 a$
$∴ s_{2} = 3 s_{1}$

Q. A particle experiences constant acceleration for 20 seconds after starting from rest. If it travels a distance s1​ in the first 10 seconds and distance s2​ in the next 10 seconds, then

s2​ = s1​

s2​ = 2s1​

s2​ = 3s1​

s2​ = 4s1​