A particle experiences a constant acceleration for 50 second after starting from rest. If it travels a distance s 1 in first 25 second and distance s 2 in the next 25 sec, then :-

Question

A particle experiences a constant acceleration for 50 second after starting from rest. If it travels a distance s 1 in first 25 second and distance s 2 in the next 25 sec, then :- (A) s1=s2 (B) s 1=( s 2/3) (C) s1=(s2/2) (D) s1=(s2/4)

Tardigrade Admin · Accepted Answer

s1=(1/2) a(25)2 and s=(1/2) a(50)2=4 s1 ∴ s 2= s - s 1=3 s 1

Q. A particle experiences a constant acceleration for $50$ second after starting from rest. If it travels a distance $s_{1}$ in first $25$ second and distance $s_{2}$ in the next $25 sec$ , then :-

$s_{1} = s_{2}$

$s_{1} = \frac{s _{2}}{3}$

$s_{1} = \frac{s _{2}}{2}$

$s_{1} = \frac{s _{2}}{4}$

$s_{1} = \frac{1}{2} a (25)^{2}$ and $s = \frac{1}{2} a (50)^{2} = 4 s_{1}$
$∴ s_{2} = s - s_{1} = 3 s_{1}$

Q. A particle experiences a constant acceleration for 50 second after starting from rest. If it travels a distance s1​ in first 25 second and distance s2​ in the next 25sec, then :-

s1​=s2​

s1​=3s2​​

s1​=2s2​​

s1​=4s2​​