A part of a complete circuit is shown in the figure. At some instant, the value of current I is 1A and it is decreasing at a rate of 102As- 1. The value of the potential difference Vp-VQ' (in volts) at that instant, is.

Question

A part of a complete circuit is shown in the figure. At some instant, the value of current I is 1A and it is decreasing at a rate of 102As- 1. The value of the potential difference Vp-VQ' (in volts) at that instant, is. <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-n3qbfchkdpsmgz6q.jpg" /> (A)  (B)  (C)  (D)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-n3qbfchkdpsmscbf.jpg" /> Vp+L⋅ (d i/d t)-30+2i=VQ Vp+50 × 10-3(-102)-30+2 × 1=vQ Vp-VQ=35-2=33

Q. A part of a complete circuit is shown in the figure. At some instant, the value of current I is $1 A$ and it is decreasing at a rate of $1 0^{2} A s^{- 1} .$ The value of the potential difference $V_{p} - V_{Q^{^{'}}}$ (in volts) at that instant, is_____.

$V_{p} + L \cdot \frac{d i}{d t} - 30 + 2 i = V_{Q}$
$V_{p} + 50 \times 1 0^{- 3} (- 1 0^{2}) - 30 + 2 \times 1 = v_{Q}$
$V_{p} - V_{Q} = 35 - 2 = 33$

Q. A part of a complete circuit is shown in the figure. At some instant, the value of current I is 1A and it is decreasing at a rate of 102As−1. The value of the potential difference Vp​−VQ′​ (in volts) at that instant, is_____.

Vp​+L⋅dtdi​−30+2i=VQ​ Vp​+50×10−3(−102)−30+2×1=vQ​ Vp​−VQ​=35−2=33

Q. A part of a complete circuit is shown in the figure. At some instant, the value of current I is $1 A$ and it is decreasing at a rate of $1 0^{2} A s^{- 1} .$ The value of the potential difference $V_{p} - V_{Q^{^{'}}}$ (in volts) at that instant, is_____.

$V_{p} + L \cdot \frac{d i}{d t} - 30 + 2 i = V_{Q}$
$V_{p} + 50 \times 1 0^{- 3} (- 1 0^{2}) - 30 + 2 \times 1 = v_{Q}$
$V_{p} - V_{Q} = 35 - 2 = 33$