A paramagnetic substance of susceptibility 3× 10- 4 is placed in a magnetic field of 3× 10- 4 A m- 1 . Then, the intensity of magnetisation in units of A m- 1 is

Question

A paramagnetic substance of susceptibility 3× 10- 4 is placed in a magnetic field of 3× 10- 4 A m- 1 . Then, the intensity of magnetisation in units of A m- 1 is (A) 9× 10- 8 (B) 1× 10- 4 (C) 1× 10- 3 (D) 9× 10- 10

Tardigrade Admin · Accepted Answer

Given, susceptibility, chi=3× 10- 4 Magnetic field, B=3× 10- 4Am- 1 Since, the intensity of magnetization, I=susceptibility× magnetic field =3× 10- 4× 3× 10- 4 =9× 10- 8Am- 1

Q. A paramagnetic substance of susceptibility $3 \times 1 0^{- 4}$ is placed in a magnetic field of $3 \times 1 0^{- 4} A m^{- 1}$ . Then, the intensity of magnetisation in units of $A m^{- 1}$ is

$9 \times 1 0^{- 8}$

$1 \times 1 0^{- 4}$

$1 \times 1 0^{- 3}$

$9 \times 1 0^{- 10}$

Given, susceptibility, $χ = 3 \times 1 0^{- 4}$
Magnetic field, $B = 3 \times 1 0^{- 4} A m^{- 1}$
Since, the intensity of magnetization,
$I = s u sce pt ibi l i t y \times ma g n e t i c f i e l d$
$= 3 \times 1 0^{- 4} \times 3 \times 1 0^{- 4}$
$= 9 \times 1 0^{- 8} A m^{- 1}$

Q. A paramagnetic substance of susceptibility 3×10−4 is placed in a magnetic field of 3×10−4Am−1 . Then, the intensity of magnetisation in units of Am−1 is

9×10−8

1×10−4

1×10−3

9×10−10