A paramagnetic substance of susceptibility 3× 10-4 is placed in a magnetic field of 4× 10-4Am-1 . Then the intensity of .magnetization in the units of Am-1 is

Question

A paramagnetic substance of susceptibility 3× 10-4 is placed in a magnetic field of 4× 10-4Am-1 . Then the intensity of .magnetization in the units of Am-1 is (A)  1.33× 108  (B)  0.75× 10-8  (C)  12× 10-8  (D)  14× 10-8

Tardigrade Admin · Accepted Answer

Susceptibility ( chi ) =(intensity text of text magnetisation(I)/magnetic text field(B)) or I= chi B ∴ I=3× 10-4× 4× 10-4 or I=12× 10-8Am-1

Q. A paramagnetic substance of susceptibility $3 \times 10^{- 4}$ is placed in a magnetic field of $4 \times 10^{- 4} A m^{- 1}$ . Then the intensity of .magnetization in the units of $A m^{- 1}$ is

$1.33 \times 10^{8}$

$0.75 \times 10^{- 8}$

$12 \times 10^{- 8}$

$14 \times 10^{- 8}$

$1.2 \times 10^{- 8}$

Susceptibility $(χ)$ $= \frac{in t e n s i t y o f ma g n e t i s a t i o n ( I )}{ma g n e t i c f i e l d ( B )}$
or $I = χ B$
$∴$ $I = 3 \times 10^{- 4} \times 4 \times 10^{- 4}$
or $I = 12 \times 10^{- 8} A m^{- 1}$

Q. A paramagnetic substance of susceptibility 3×10−4 is placed in a magnetic field of 4×10−4Am−1 . Then the intensity of .magnetization in the units of Am−1 is

1.33×108

0.75×10−8

12×10−8

14×10−8

1.2×10−8

Susceptibility (χ) =magneticfield(B)intensityofmagnetisation(I)​ or I=χB ∴ I=3×10−4×4×10−4 or I=12×10−8Am−1