A parallelepiped is formed by planes drawn through the points (2, 3, 5) and (5, 9, 7) parallel to the coordinate planes. The length of a diagonal of the parallelepiped to piped is:

Question

A parallelepiped is formed by planes drawn through the points (2, 3, 5) and (5, 9, 7) parallel to the coordinate planes. The length of a diagonal of the parallelepiped to piped is: (A)  7  (B)  √38  (C)  √155  (D) none of these

Tardigrade Admin · Accepted Answer

The length of the edges are given by a=5-2=3 , b=9-3=6 and c=7-5=2 So, length of the diagonal =√9+36+4 =7

Q. A parallelepiped is formed by planes drawn through the points $(2, 3, 5)$ and $(5, 9, 7)$ parallel to the coordinate planes. The length of a diagonal of the parallelepiped to piped is:

$7$

$38$

$155$

none of these

The length of the edges are given by
$a = 5 - 2 = 3$ , $b = 9 - 3 = 6$ and $c = 7 - 5 = 2$
So, length of the diagonal
$= 9 + 36 + 4$ $= 7$

Q. A parallelepiped is formed by planes drawn through the points (2,3,5) and (5,9,7) parallel to the coordinate planes. The length of a diagonal of the parallelepiped to piped is:

7

38​

155​

none of these

The length of the edges are given by a=5−2=3 , b=9−3=6 and c=7−5=2 So, length of the diagonal =9+36+4​ =7

Q. A parallelepiped is formed by planes drawn through the points $(2, 3, 5)$ and $(5, 9, 7)$ parallel to the coordinate planes. The length of a diagonal of the parallelepiped to piped is:

$7$

$38$

$155$

The length of the edges are given by
$a = 5 - 2 = 3$ , $b = 9 - 3 = 6$ and $c = 7 - 5 = 2$
So, length of the diagonal
$= 9 + 36 + 4$ $= 7$