A parallel plate capacitor (PPC) has 1 μ F capacitance. Charge of +4 μ C is given to one plate &+2 μ C to other plate. Find potential difference across the capacitor.

Question

A parallel plate capacitor (PPC) has 1 μ F capacitance. Charge of +4 μ C is given to one plate &+2 μ C to other plate. Find potential difference across the capacitor. (A) 1 V (B) 2 V (C) 3 V (D) 5 V

Tardigrade Admin · Accepted Answer

Δ V =( Q 1- Q 2/2 C ) =(4 μ-2 μ/2 × 1 μ)=1 V

Q. A parallel plate capacitor (PPC) has $1 μ F$ capacitance. Charge of $+ 4 μ C$ is given to one plate $& + 2 μ C$ to other plate. Find potential difference across the capacitor.

1 V

2 V

3 V

5 V

$Δ V = \frac{Q _{1} - Q _{2}}{2 C}$
$= \frac{4 μ - 2 μ}{2 \times 1 μ} = 1 V$

Q. A parallel plate capacitor (PPC) has 1μF capacitance. Charge of +4μC is given to one plate &+2μC to other plate. Find potential difference across the capacitor.

1 V

2 V

3 V

5 V

ΔV=2CQ1​−Q2​​ =2×1μ4μ−2μ​=1V

Q. A parallel plate capacitor (PPC) has $1 μ F$ capacitance. Charge of $+ 4 μ C$ is given to one plate $& + 2 μ C$ to other plate. Find potential difference across the capacitor.

$Δ V = \frac{Q _{1} - Q _{2}}{2 C}$
$= \frac{4 μ - 2 μ}{2 \times 1 μ} = 1 V$