A parallel plate capacitor of capacitance 1 μF is charged on both the plates +2 μC and +4 μC respectively . The potential difference developed across the capacitor is:

Question

A parallel plate capacitor of capacitance 1 μF is charged on both the plates +2 μC and +4 μC respectively . The potential difference developed across the capacitor is: (A) 5V (B) 2V (C) 3V (D) 1V

Tardigrade Admin · Accepted Answer

Charge on capacitor plate is given by, Q=(Q1 - Q2/2) ⇒ Q=(4 - 2/2)=1Î¼C V=(Q/C)=(1 Î¼C/1 Î¼F)=1 Volt

Q. A parallel plate capacitor of capacitance $1 μ F$ is charged on both the plates $+ 2 μ C$ and $+ 4 μ C$ respectively . The potential difference developed across the capacitor is:

$5 V$

$2 V$

$3 V$

$1 V$

Charge on capacitor plate is given by, $Q = \frac{Q _{1} - Q _{2}}{2}$
$\Rightarrow Q = \frac{4 - 2}{2} = 1 μ C$
$V = \frac{Q}{C} = \frac{1 μ C}{1 μ F} = 1$ Volt

Q. A parallel plate capacitor of capacitance 1μF is charged on both the plates +2μC and +4μC respectively . The potential difference developed across the capacitor is:

5V

2V

3V

1V