A parallel plate capacitor is made by placing n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is C then the resultant capacitance is

Question

A parallel plate capacitor is made by placing n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is C then the resultant capacitance is (A) nC (B) (C/n) (C) (n+1)C (D) (n-1)C

Tardigrade Admin · Accepted Answer

When n equally spaced plates are connected alternatively, (n-1) capacitors, each of capacity C are formed. As they are joined in parallel, ∴ Ceq = (n-1)C

Q. A parallel plate capacitor is made by placing $n$ equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is $C$ then the resultant capacitance is

$n C$

$\frac{C}{n}$

$(n + 1) C$

$(n - 1) C$

When $n$ equally spaced plates are connected alternatively, $(n - 1)$ capacitors, each of capacity $C$ are formed. As they are joined in parallel,
$∴ C_{e q} = (n - 1) C$

Q. A parallel plate capacitor is made by placing n equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is C then the resultant capacitance is

nC

nC​

(n+1)C

(n−1)C