Question

A parallel plate capacitor is made by placing $n$ equally spaced plates connected alternatively. If the capacitance between any two adjacent plates is $C$ then the resultant capacitance is

• A. $nC$
• B. $\frac{C}{n}$
• C. $\left(n+1\right)C$
• D. $\left(n-1\right)C$

Answer 1

Answer: (D)

When $n$ equally spaced plates are connected alternatively, $(n-1)$ capacitors, each of capacity $C$ are formed. As they are joined in parallel,
$\therefore C_{eq} = \left(n-1\right)C$