A parallel plate capacitor is formed by two plates each of area 30 π cm 2 separated by 1 mm. A material of dielectric strength 3.6 × 107 Vm -1 is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is 7 × 10-6 C, the value of dielectric constant of the material is: text Use: (1/4 π ε0)=9 × 109 Nm 2 C -2

Question

A parallel plate capacitor is formed by two plates each of area 30 π cm 2 separated by 1 mm. A material of dielectric strength 3.6 × 107 Vm -1 is filled between the plates. If the maximum charge that can be stored on the capacitor without causing any dielectric breakdown is 7 × 10-6 C, the value of dielectric constant of the material is: text Use: (1/4 π ε0)=9 × 109 Nm 2 C -2  (A) 1.66 (B) 1.75 (C) 2.25 (D) 2.33

Tardigrade Admin · Accepted Answer

K =( q / A ∈0 E )=(7 × 10-6/30 π × 10-4 × (1)4 π × 9 × 109 × 3.6 × 107) K =(36 × 7/30 × 3.6)=2.33

1.66

1.75

2.25

2.33

K=A∈0​Eq​=30π×10−4×4π×9×1091​×3.6×1077×10−6​ K=30×3.636×7​=2.33

$K = \frac{q}{A \in _{0} E} = \frac{7 \times 1 0 ^{- 6}}{30 π \times 1 0 ^{- 4} \times \frac{1}{4 π \times 9 \times 1 0 ^{9}} \times 3.6 \times 1 0 ^{7}}$
$K = \frac{36 \times 7}{30 \times 3.6} = 2.33$