A parallel plate capacitor has an electric field of 105 V / m between the plates. If the charge on the capacitor plate is 1 μ C, the force on each capacitor plate is

Question

A parallel plate capacitor has an electric field of 105 V / m between the plates. If the charge on the capacitor plate is 1 μ C, the force on each capacitor plate is (A) 0.5 N (B) 0.005 N (C) 0.05 N (D) 0.0005 N

Tardigrade Admin · Accepted Answer

E=105 V / m , q=1 μ C =10-6 C F=(q2/2 ε0 A) and E=(q/ε0 A) ∴ F=(q E/2)=(10-6 × 105/2)=0.05 N

Q. A parallel plate capacitor has an electric field of $1 0^{5} V / m$ between the plates. If the charge on the capacitor plate is $1 μ C$ , the force on each capacitor plate is

0.5 N

0.005 N

0.05 N

0.0005 N

$E = 1 0^{5} V / m, q = 1 μ C = 1 0^{- 6} C$
$F = \frac{q ^{2}}{2 ε _{0} A}$ and $E = \frac{q}{ε _{0} A}$
$∴ F = \frac{qE}{2} = \frac{1 0 ^{- 6} \times 1 0 ^{5}}{2} = 0.05 N$

Q. A parallel plate capacitor has an electric field of 105V/m between the plates. If the charge on the capacitor plate is 1μC, the force on each capacitor plate is