A parallel plate capacitor consists of two circular plates each of radius 2 cm, separated by a distance of 0.1 mm. If voltage across the plates is varying at the rate of 5 × 1013 V / s, then the value of displacement current is

Question

A parallel plate capacitor consists of two circular plates each of radius 2 cm, separated by a distance of 0.1 mm. If voltage across the plates is varying at the rate of 5 × 1013 V / s, then the value of displacement current is (A) 5.50 A (B) 5.56 × 102 A (C) 5.56 × 103 A (D) 2.28 × 104 A

Tardigrade Admin · Accepted Answer

Id =ε0 A (d E/d t)=ε0 (A/d) (d V/d t) =(8.86 × 10-12 × 3.14 ×(2 × 10-2)2/0.1 × 10-3) × 5 × 1013 =5.56 × 103 A

Q. A parallel plate capacitor consists of two circular plates each of radius $2 c m$ , separated by a distance of $0.1 mm$ . If voltage across the plates is varying at the rate of $5 \times 1 0^{13} V / s$ , then the value of displacement current is

$5.50 A$

$5.56 \times 1 0^{2} A$

$5.56 \times 1 0^{3} A$

$2.28 \times 1 0^{4} A$

$I_{d} = ε_{0} A \frac{d E}{d t} = ε_{0} \frac{A}{d} \frac{d V}{d t}$
$= \frac{8.86 \times 1 0 ^{- 12} \times 3.14 \times ( 2 \times 1 0 ^{- 2} ) ^{2}}{0.1 \times 1 0 ^{- 3}} \times 5 \times 1 0^{13}$
$= 5.56 \times 1 0^{3} A$

Q. A parallel plate capacitor consists of two circular plates each of radius 2cm, separated by a distance of 0.1mm. If voltage across the plates is varying at the rate of 5×1013V/s, then the value of displacement current is

5.50A

5.56×102A

5.56×103A

2.28×104A