A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2m/s2 He reaches the ground with a speed of 3m /s, At what height, did he bail out

Question

A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2m/s2 He reaches the ground with a speed of 3m /s, At what height, did he bail out (A) 91 m (B) 182 m (C) 293 m (D) 111 m

Tardigrade Admin · Accepted Answer

u = √2g × 50 (g = 9.8 m/s2) ν2 - u2 = 2as height at which he bails out = (50 + s)

Q. A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at $2 m / s^{2}$ He reaches the ground with a speed of $3 m / s$ , At what height, did he bail out

91 m

182 m

293 m

111 m

u = $2 g \times 50$ (g = 9.8 m/s $^{2}$ )
$ν^{2} - u^{2} = 2 a s$
height at which he bails out = (50 + s)

Q. A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2m/s2 He reaches the ground with a speed of 3m/s, At what height, did he bail out