A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at 2 m/s2. He reaches the ground with a speed of 3 m/s. At what height, did he bail out ?

Question

A parachutist after bailing out falls 50 m without friction. When parachute opens, it decelerates at 2 m/s2. He reaches the ground with a speed of 3 m/s. At what height, did he bail out ? (A) 91 m (B) 182 m (C) 293 m (D) 111 m

Tardigrade Admin · Accepted Answer

Parachute bails out at height H from ground.Velocity at A v=√2gh =√2×9.8×50 =√980 m/s The velocity at ground v1=3 m/s (given) Acceleration = - 2 m/s2 (given) ∴ H-h=(v2-v21/2×2) =(980-9/4) =(971/4)=242.75 ∴ H=242.75+ h =242.75+50≈293 m

Q. A parachutist after bailing out falls $50 m$ without friction. When parachute opens, it decelerates at $2 m / s^{2}$ . He reaches the ground with a speed of $3 m / s$ . At what height, did he bail out ?

$91 m$

$182 m$

$293 m$

$111 m$

Q. A parachutist after bailing out falls 50m without friction. When parachute opens, it decelerates at 2m/s2. He reaches the ground with a speed of 3m/s. At what height, did he bail out ?

91m

182m

293m

111m

Parachute bails out at height H from ground.Velocity at A v=2gh​ =2×9.8×50​ =980​m/s The velocity at ground v1​=3m/s (given) Acceleration =−2m/s2 (given) ∴H−h=2×2v2−v12​​ =4980−9​ =4971​=242.75 ∴H=242.75+h =242.75+50≈293m

Q. A parachutist after bailing out falls $50 m$ without friction. When parachute opens, it decelerates at $2 m / s^{2}$ . He reaches the ground with a speed of $3 m / s$ . At what height, did he bail out ?

$91 m$

$182 m$

$293 m$

$111 m$