A p-type semiconductor has acceptor levels 57 MeV above the valence band. The maximum wavelength of light required to create a hole is

Question

A p-type semiconductor has acceptor levels 57 MeV above the valence band. The maximum wavelength of light required to create a hole is (A) 57 overset texto mathop textA  (B)  57× 10-3 overset texto mathop textA  (C) 217100 overset texto mathop textA  (D)  11.61× 10-33 overset texto mathop textA (Plancks constant h=6.6× 10-34 Js)

Tardigrade Admin · Accepted Answer

The energy of photon =(hc/λ ), which should be equal to 57 MeV =57× 10-3× 1.6× 10-19J Therefore, λ =(6.6× 10-34× 3× 108/57× 10-3× 1.6× 10-19) =0.2171× 10-4m =217100 overset texto mathop textA

Q. A p-type semiconductor has acceptor levels 57 MeV above the valence band. The maximum wavelength of light required to create a hole is

57 $A o$

$57 \times 10^{- 3}$ $A o$

217100 $A o$

$11.61 \times 10^{- 33}$ $A o$ (Plancks constant $h = 6.6 \times 10^{- 34}$ Js)

The energy of photon $= \frac{h c}{λ},$ which should be equal to 57 MeV $= 57 \times 10^{- 3} \times 1.6 \times 10^{- 19} J$ Therefore, $λ = \frac{6.6 \times 10 ^{- 34} \times 3 \times 10 ^{8}}{57 \times 10 ^{- 3} \times 1.6 \times 10 ^{- 19}}$ $= 0.2171 \times 10^{- 4} m$ $= 217100 A o$

Q. A p-type semiconductor has acceptor levels 57 MeV above the valence band. The maximum wavelength of light required to create a hole is

57 Ao

57×10−3 Ao

217100 Ao

11.61×10−33 Ao (Plancks constant h=6.6×10−34 Js)

The energy of photon =λhc​, which should be equal to 57 MeV =57×10−3×1.6×10−19J Therefore, λ=57×10−3×1.6×10−196.6×10−34×3×108​ =0.2171×10−4m =217100Ao

57 $A o$

$57 \times 10^{- 3}$ $A o$

217100 $A o$

$11.61 \times 10^{- 33}$ $A o$ (Plancks constant $h = 6.6 \times 10^{- 34}$ Js)

The energy of photon $= \frac{h c}{λ},$ which should be equal to 57 MeV $= 57 \times 10^{- 3} \times 1.6 \times 10^{- 19} J$ Therefore, $λ = \frac{6.6 \times 10 ^{- 34} \times 3 \times 10 ^{8}}{57 \times 10 ^{- 3} \times 1.6 \times 10 ^{- 19}}$ $= 0.2171 \times 10^{- 4} m$ $= 217100 A o$