A one-ton car moves with a constant velocity of 15 ms -1 on a rough horizontal road. The total resistance to the motion of the car is 12 % of the weight of the car. The power required to keep the car moving with the same constant velocity of 15 ms -1 is [Take g=10 ms -2 ].

Question

A one-ton car moves with a constant velocity of 15 ms -1 on a rough horizontal road. The total resistance to the motion of the car is 12 % of the weight of the car. The power required to keep the car moving with the same constant velocity of 15 ms -1 is [Take g=10 ms -2 ]. (A) 9 kW (B) 18 kW (C) 24 kW (D) 36 kW

Tardigrade Admin · Accepted Answer

Resistance force =(12/100) ×(1000 kg )(10 ( m / s 2)) =1200 N P text required =(F)(v)=(1200 N )(15 ( m / s ))=18000 W =18 kW

Q. A one-ton car moves with a constant velocity of $15 m s^{- 1}$ on a rough horizontal road. The total resistance to the motion of the car is $12%$ of the weight of the car. The power required to keep the car moving with the same constant velocity of $15 m s^{- 1}$ is [Take $g = 10 m s^{- 2}$ ].

9 kW

18 kW

24 kW

36 kW

Resistance force $= \frac{12}{100} \times (1000 k g) (10 \frac{m}{s ^{2}})$
$= 1200 N$
$P_{required} = (F) (v) = (1200 N) (15 \frac{m}{s}) = 18000 W = 18 kW$

Q. A one-ton car moves with a constant velocity of 15ms−1 on a rough horizontal road. The total resistance to the motion of the car is 12% of the weight of the car. The power required to keep the car moving with the same constant velocity of 15ms−1 is [Take g=10ms−2 ].