Q.
A nucleus with mass number 220 initially at rest emits an α -particle. If the Q value of the reaction is 5.5MeV , then calculate the kinetic energy of the α -particle.
Given that K1+K2=5.5MeV ... (i)
From conservation of linear momentum, p1=p2 2K1(216m)=2K2(4m) (As p=2Km ) K2=54K1 ... (ii)
Solving Eqs. (i) and (ii), we get K2= K.E. of α -particle 5.4MeV .