A nuclei X with mass number A and charge number Z, disintegrates into one α-particle and one β-particle. The resulting nuclide R has atomic mass and atomic number, equal to :

Question

A nuclei X with mass number A and charge number Z, disintegrates into one α-particle and one β-particle. The resulting nuclide R has atomic mass and atomic number, equal to : (A) (A - Z) and (Z - 1) (B) (A- Z) and (Z- 2) (C) (A - 4) and (A - 2) (D) (A - 4) and (Z- 1)

Tardigrade Admin · Accepted Answer

When an α-particle is emitted, mass number of nuclide X is reduced to 4, and its charge number is reduced to 2, But when a β-particle is emitted, mass number of remains the same and its charge number is increased by 1. Hence, the resulting nuclide has atomic mass A-4 and atomic number Z-1.

Q. A nuclei X with mass number A and charge number Z, disintegrates into one α-particle and one β-particle. The resulting nuclide R has atomic mass and atomic number, equal to :

(A - Z) and (Z - 1)

(A- Z) and (Z- 2)

(A - 4) and (A - 2)

(A - 4) and (Z- 1)

When an α-particle is emitted, mass number of nuclide X is reduced to 4, and its charge number is reduced to 2, But when a β-particle is emitted, mass number of remains the same and its charge number is increased by 1. Hence, the resulting nuclide has atomic mass A−4 and atomic number Z−1.

Q. A nuclei $X$ with mass number $A$ and charge number $Z$ , disintegrates into one $α$ -particle and one $β$ -particle. The resulting nuclide $R$ has atomic mass and atomic number, equal to :