Question

A network of four $10\mu F$ capacitors is connected to a $500V$ supply as shown in figure. Determine the equivalent capacitance of the network.

• A. $12\mu F$
• B. $13.3\mu F$
• C. $11.5\mu F$
• D. $14\mu F$

Answer 1

Answer: (B)

In the given network, $C_1,C_2$ and $C_3$ are connected in series.
The effective capacitance $C^{\prime }$ of these capacitors is given by
$\frac{1}{C^{\prime }}-\frac{1}{C_1}+\frac{1}{C_2}+\frac{1}{C_3}$
For $C_1=C_2=C_3=10\mu F,C^{\prime }=(10/3)\mu F$
The network has $C^{\prime }$ and $C_4$ connected in parallel.
Thus, the equivalent capacitance $C$ of the network is
$C=C^{\prime }+C_4=\left(\frac{10}{3}+10\right)=13.3\mu F$