A mutant strain of T 4-bacteriophage R-II, fails to lyse the E.coli but when two strains R-II x and R - II y are mixed then they lyse the E.coli. What may be the possible reason?

Question

A mutant strain of T 4-bacteriophage R-II, fails to lyse the E.coli but when two strains R-II x and R - II y are mixed then they lyse the E.coli. What may be the possible reason? (A) Bacteriophage transforms in wild (B) It is not mutated (C) Both strains have similar cistrons (D) Both strains have different cistrons

Tardigrade Admin · Accepted Answer

The enzymes required for lysing E. coli could not be synthesised by the mutant strain. Two different strains had cistrons for synthesizing two different enzymes which acted together.

Q. A mutant strain of T4​-bacteriophage R-II, fails to lyse the E.coli but when two strains R-II x and R−IIy are mixed then they lyse the E.coli. What may be the possible reason?

Bacteriophage transforms in wild

It is not mutated

Both strains have similar cistrons

Both strains have different cistrons

The enzymes required for lysing E. coli could not be synthesised by the mutant strain. Two different strains had cistrons for synthesizing two different enzymes which acted together.

Q. A mutant strain of $T_{4}$ -bacteriophage $R$ -II, fails to lyse the E.coli but when two strains $R$ -II $^{x}$ and $R - I I^{y}$ are mixed then they lyse the $E$ .coli. What may be the possible reason?