A musician on a moving vehicle plays a tone at 880 Hz note. When the vehicle was approaching a listener, he receives it as 888 Hz tone. The speed of the vehicle is (Assume the velocity of sound is 333 m / s.)

Question

A musician on a moving vehicle plays a tone at 880 Hz note. When the vehicle was approaching a listener, he receives it as 888 Hz tone. The speed of the vehicle is (Assume the velocity of sound is 333 m / s.) (A) 6 m / s (B) 5 m / s (C) 3 m / s (D) 1 m / s

Tardigrade Admin · Accepted Answer

Given, n0=880 Hz (Frequency of sound produced by musician), n=888 Hz (frequency of sound observed by observer and speed of sound, v=333 m / s ). We know that, when sound source is in motion and observer is stationary, frequency heard, n =(n0 v/v-vs) ⇒ vs=v[1-(n0/n)] ⇒ vs =333[1-(880/888)]=3 m / s

Q. A musician on a moving vehicle plays a tone at 880Hz note. When the vehicle was approaching a listener, he receives it as 888Hz tone. The speed of the vehicle is (Assume the velocity of sound is 333m/s.)

6 m / s

5 m / s

3 m / s

1 m / s

Q. A musician on a moving vehicle plays a tone at $880 Hz$ note. When the vehicle was approaching a listener, he receives it as $888 Hz$ tone. The speed of the vehicle is (Assume the velocity of sound is $333 m / s$ .)