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Q. A musician on a moving vehicle plays a tone at $880\, Hz$ note. When the vehicle was approaching a listener, he receives it as $888\, Hz$ tone. The speed of the vehicle is (Assume the velocity of sound is $333\, m / s$.)

TS EAMCET 2019

Solution:

Given, $n_{0}=880\, Hz$ (Frequency of sound produced by musician), $n=888\, Hz$ (frequency of sound observed by observer and speed of sound, $v=333\, m / s$ ).
We know that, when sound source is in motion and observer is stationary, frequency heard,
$n =\frac{n_{0} v}{v-v_{s}}$
$\Rightarrow v_{s}=v\left[1-\frac{n_{0}}{n}\right]$
$\Rightarrow v_{s} =333\left[1-\frac{880}{888}\right]=3\, m / s$