A moving coil galvanometer has resistance 50Ω and it indicates full deflection at 4mA current. A voltmeter is made using this galvanometer and a 5 kΩ resistance. The maximum voltage, that can be measured using this voltmeter, will be close to :

Question

A moving coil galvanometer has resistance 50Ω and it indicates full deflection at 4mA current. A voltmeter is made using this galvanometer and a 5 kΩ resistance. The maximum voltage, that can be measured using this voltmeter, will be close to : (A) 10 V (B) 20 V (C) 40 V (D) 15 V

Tardigrade Admin · Accepted Answer

G = 50 Ω S = 5000 Ω ig = 4 × 10-3 V = ig (G + S) V = 4 × 10-3 (50 + 5000) = 4 × 10-3(5050) = 20.2 volt Option (2)

Q. A moving coil galvanometer has resistance 50 $Ω$ and it indicates full deflection at 4mA current. A voltmeter is made using this galvanometer and a 5 k $Ω$ resistance. The maximum voltage, that can be measured using this voltmeter, will be close to :

10 V

20 V

40 V

15 V

G = 50 $Ω$
S = 5000 $Ω$
i $_{g}$ = 4 × 10 $_{- 3}$
V = i $_{g}$ (G + S)
V = 4 × 10 $- 3$ (50 + 5000)
= 4 × 10 $^{- 3}$ (5050)
= 20.2 volt
Option (2)

Q. A moving coil galvanometer has resistance 50Ω and it indicates full deflection at 4mA current. A voltmeter is made using this galvanometer and a 5 kΩ resistance. The maximum voltage, that can be measured using this voltmeter, will be close to :