A moving coil galvanometer has a rectangular wire coil of enclosed area 0.001 m 2 and 500 turns. The coil operates in a radial magnetic field of 0.2 T and carries a current of 6 π × 10-8 A. If the torsional spring constant is 6 × 10-7 N - m / rad, then the angular deflection of the coil in radians is

Question

A moving coil galvanometer has a rectangular wire coil of enclosed area 0.001 m 2 and 500 turns. The coil operates in a radial magnetic field of 0.2 T and carries a current of 6 π × 10-8 A. If the torsional spring constant is 6 × 10-7 N - m / rad, then the angular deflection of the coil in radians is (A) (π/100) (B) (π/200) (C) (π/300) (D) (π/400)

Tardigrade Admin · Accepted Answer

Angular deflection of a moving coil galvanometer is given by θ =((N B A/k)) i =(500 × 0.2 × 0.001/6 × 10-7) × 6 π × 10-8 =(5 × 0.2 × 10-1 × 6 π × 10-8/6 × 10-7) θ =(π/100)

$\frac{π}{100}$

$\frac{π}{200}$

$\frac{π}{300}$

$\frac{π}{400}$

Angular deflection of a moving coil galvanometer is given by
$θ = (\frac{NB A}{k}) i$
$= \frac{500 \times 0.2 \times 0.001}{6 \times 1 0 ^{- 7}} \times 6 π \times 1 0^{- 8}$
$= \frac{5 \times 0.2 \times 1 0 ^{- 1} \times 6 π \times 1 0 ^{- 8}}{6 \times 1 0 ^{- 7}}$
$θ = \frac{π}{100}$

Q. A moving coil galvanometer has a rectangular wire coil of enclosed area 0.001m2 and 500 turns. The coil operates in a radial magnetic field of 0.2T and carries a current of 6π×10−8A. If the torsional spring constant is 6×10−7N−m/rad, then the angular deflection of the coil in radians is

100π​

200π​

300π​

400π​

Angular deflection of a moving coil galvanometer is given by θ=(kNBA​)i =6×10−7500×0.2×0.001​×6π×10−8 =6×10−75×0.2×10−1×6π×10−8​ θ=100π​

$\frac{π}{100}$

$\frac{π}{200}$

$\frac{π}{300}$

$\frac{π}{400}$

Angular deflection of a moving coil galvanometer is given by
$θ = (\frac{NB A}{k}) i$
$= \frac{500 \times 0.2 \times 0.001}{6 \times 1 0 ^{- 7}} \times 6 π \times 1 0^{- 8}$
$= \frac{5 \times 0.2 \times 1 0 ^{- 1} \times 6 π \times 1 0 ^{- 8}}{6 \times 1 0 ^{- 7}}$
$θ = \frac{π}{100}$