A motor car is moving with a speed of 20 text ms-1 on a circular track of radius 100 m. If its speed is increasing at the rate of 3ms-1, its resultant acceleration is

Question

A motor car is moving with a speed of 20 text ms-1 on a circular track of radius 100 m. If its speed is increasing at the rate of 3ms-1, its resultant acceleration is (A)  3 ms-2  (B)  5 ms-2  (C)  2.5 ms-2  (D)  3.5 ms-2

Tardigrade Admin · Accepted Answer

Resultant acceleration, a=√ac2+at2 =√( (v2/r) )+(3)2=√( (20× 20/100) )2+9 =√16+9=5 ms-2

Q. A motor car is moving with a speed of $20 m s^{- 1}$ on a circular track of radius $100 m$ . If its speed is increasing at the rate of $3 m s^{- 1},$ its resultant acceleration is

$3 m s^{- 2}$

$5 m s^{- 2}$

$2.5 m s^{- 2}$

$3.5 m s^{- 2}$

$4 m s^{- 2}$

Resultant acceleration,
$a = a_{c}^{2} + a_{t}^{2}$
$= (\frac{v ^{2}}{r}) + (3)^{2} = (\frac{20 \times 20}{100})^{2} + 9$
$= 16 + 9 = 5 m s^{- 2}$

Q. A motor car is moving with a speed of 20ms−1 on a circular track of radius 100m. If its speed is increasing at the rate of 3ms−1, its resultant acceleration is

3ms−2

5ms−2

2.5ms−2

3.5ms−2

4ms−2

Resultant acceleration, a=ac2​+at2​​ =(rv2​)+(3)2​=(10020×20​)2+9​ =16+9​=5ms−2