A monochromatic source of light emits photons of frequency 6 × 1014 Hz . The power emitted by the source is 8 × 10-3W . Calculate the number of photons emitted per second (Take h = 6.63× 10-34 J- s )

Question

A monochromatic source of light emits photons of frequency 6 × 1014 Hz . The power emitted by the source is 8 × 10-3W . Calculate the number of photons emitted per second (Take h = 6.63× 10-34 J- s ) (A)  6 × 1014  (B)  4 × 1015  (C)  2 × 1016  (D)  1 × 1017

Tardigrade Admin · Accepted Answer

The number of photons emitted per second from a source of monochromatic radiation of wavelength λ and power P is given by n =(P/hv) = (8 × 10-3/6.63 × 10-34 × 6 × 1014) = 2× 1016

Q. A monochromatic source of light emits photons of frequency $6 \times 1 0^{14} Hz$ . The power emitted by the source is $8 \times 1 0^{- 3} W$ . Calculate the number of photons emitted per second (Take $h = 6.63 \times 1 0^{- 34} J - s$ )

$6 \times 1 0^{14}$

$4 \times 1 0^{15}$

$2 \times 1 0^{16}$

$1 \times 1 0^{17}$

The number of photons emitted per second from a source of monochromatic radiation of wavelength $λ$ and power $P$ is given by
$n = \frac{P}{h v}$
$= \frac{8 \times 1 0 ^{- 3}}{6.63 \times 1 0 ^{- 34} \times 6 \times 1 0 ^{14}}$
$= 2 \times 1 0^{16}$

Q. A monochromatic source of light emits photons of frequency 6×1014Hz . The power emitted by the source is 8×10−3W . Calculate the number of photons emitted per second (Take h=6.63×10−34J−s )

6×1014

4×1015

2×1016

1×1017