A monochromatic light of wavelength 6500 oversetoA is used in YDSE . Now both slits are covered by two thin slits of refractive index 3.2 and 2.7 respectively. By doing so central bright fringe shifts to original 7th bright fringe. If both slits have same thickness then it is equal to

Question

A monochromatic light of wavelength 6500 oversetoA is used in YDSE . Now both slits are covered by two thin slits of refractive index 3.2 and 2.7 respectively. By doing so central bright fringe shifts to original 7th bright fringe. If both slits have same thickness then it is equal to (A) 7.8μm (B) 9.1μm (C) 6.5μm (D) 9.8μm

Tardigrade Admin · Accepted Answer

7× (D λ /d)=(((μ )1 - (μ )2) t ⋅ D/d) t=9.1Î¼m

Q. A monochromatic light of wavelength $6500 A o$ is used in $Y D SE$ . Now both slits are covered by two thin slits of refractive index $3.2$ and $2.7$ respectively. By doing so central bright fringe shifts to original $7^{t h}$ bright fringe. If both slits have same thickness then it is equal to

$7.8 μ m$

$9.1 μ m$

$6.5 μ m$

$9.8 μ m$

$7 \times \frac{D λ}{d} = \frac{( ( μ ) _{1} - ( μ ) _{2} ) t \cdot D}{d}$
$t = 9.1 μ m$

Q. A monochromatic light of wavelength 6500Ao is used in YDSE . Now both slits are covered by two thin slits of refractive index 3.2 and 2.7 respectively. By doing so central bright fringe shifts to original 7th bright fringe. If both slits have same thickness then it is equal to

7.8μm

9.1μm

6.5μm

9.8μm