A monoatomic gas is taken along path AB as shown. Calculate change in internal energy of system :-

Question

A monoatomic gas is taken along path AB as shown. Calculate change in internal energy of system :- <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-zv2lycuonmcpibdw.jpg" /> (A) 279.8J (B) 341J (C) 241J (D) None of these

Tardigrade Admin · Accepted Answer

Δ U=nCvΔ T=F/2(P2 V2 - P1 V1) Δ U= Zero

Q. A monoatomic gas is taken along path $A B$ as shown. Calculate change in internal energy of system :-

$279.8 J$

$341 J$

$241 J$

None of these

$Δ U = n C_{v} Δ T = F /2 (P_{2} V_{2} - P_{1} V_{1})$
$Δ U =$ Zero

Q. A monoatomic gas is taken along path AB as shown. Calculate change in internal energy of system :-

279.8J

341J

241J