Q.
A monkey of mass 50kg climbs on a rope which can withstand the tension (T) of 350N. If monkey initially climbs down with an acceleration of 4m/s2 and then climbs up with an acceleration of 5m/s2. Choose the correct option (g=10m/s2)
F.B.D of monkey while moving downward
Using Newton's second law mg−T=ma1 ∴500−T=50×4⇒T=300N
F.B.D of monkey while moving up
Using Newton's second law of motion T−mg=ma2 ⇒T−500=50×5 ⇒T=750N
Breaking strength of string =350N ∴ String will break while monkey is moving upward