Q.
A monkey of mass 40kg climbs ona massless rope which can stand a maximum tension of 500N. In which of the following cases will the rope break?
(Takeg=10ms−2)
Here, mass of monkey, m=40kg
Maximum tension the rope can stand, T=500N
Tension in the rope will be equal to apparent weight of the monkey (R).
The rope will break when R exceeds T.
(a) When the monkey climbs up with an acceleration a=5ms−2 R=m(g+a)=40(10+5)=600N∴R>T
Hence, the rope will break.
(b) When the monkey climbs down with an acceleration a=5ms−2 R=m(g−a)=40(10−5)=200N∴R<T
Hence, the rope will not break.
(c) When the monkey climbs up with a uniform speed v=5ms−1, its acceleration a = 0 ∴R=mg=40×10=400N∴R<T
Hence, the rope will not break.
(d) When the monkey falls down the rope freely under gravity a=g∴R=m(g−a)=m(g−g)=zero
Hence, the rope will not break.