A monkey (mass 20kg ) climbs up on a rope. If the rope can bear a maximum tension of 250N . Find the maximum upward acceleration of the monkey. ( textg = 1 0 ( textms)- 2)

Question

A monkey (mass 20kg ) climbs up on a rope. If the rope can bear a maximum tension of 250N . Find the maximum upward acceleration of the monkey. ( textg = 1 0 ( textms)- 2) (A) 2.5 m text​ s- 2 (B) 5 m text​ s- 2 (C) 10 m text​ s- 2 (D) 25 m text​ s- 2

Tardigrade Admin · Accepted Answer

For monkey, we can write T -Mg= Ma or M(g + a) = T ....(i) for suspended weight, T â¤ mg ....(ii) T â¤ 25 Ã 10 or 250 N [breaking strength] <img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-aaoukunis316hxyk.jpg" /> â â´ Equation (i) becomes 20.(10 + a) â¤ 250 ⇒ texta ≤ ( text50/2 0) textor texta ≤ 2 text. 5 textms- 2 â´ amax = 2.5 ms-2

Q. A monkey (mass $20 k g$ ) climbs up on a rope. If the rope can bear a maximum tension of $250 N$ . Find the maximum upward acceleration of the monkey. $(g = 10 (ms)^{- 2})$

$2.5 m s^{- 2}$

$5 m s^{- 2}$

$10 m s^{- 2}$

$25 m s^{- 2}$

For monkey, we can write
T -Mg= Ma
or M(g + a) = T ....(i)
for suspended weight,
T ≤ mg ....(ii)
T ≤ 25 × 10 or 250 N [breaking strength]

∴ Equation (i) becomes
20.(10 + a) ≤ 250
$\Rightarrow a \leq \frac{50}{20} or a \leq 2.5 ms^{- 2}$
∴ a_max = 2.5 ms^-2

Q. A monkey (mass 20kg ) climbs up on a rope. If the rope can bear a maximum tension of 250N . Find the maximum upward acceleration of the monkey. (g=10(ms)−2)

2.5m​s−2

5m​s−2

10m​s−2

25m​s−2