A mixture of two salts is used to prepare a solution S, which gives the following results: textWhite precipitate(s) only xleftarrow[ textRoom temperature] textDilute NaOH(aq) underset text(aq solution of the salts)S xrightarrow[ textRoom temperature] textDilute HCl(aq) White precipitate(s) only The correct option(s) for the salt mixture is(are)

Question

A mixture of two salts is used to prepare a solution S, which gives the following results: textWhite precipitate(s) only xleftarrow[ textRoom temperature] textDilute NaOH(aq) underset text(aq solution of the salts)S xrightarrow[ textRoom temperature] textDilute HCl(aq) White precipitate(s) only The correct option(s) for the salt mixture is(are) (A) Pb ( NO 3)2 and Zn ( NO 3)2 (B) Pb ( NO 3)2 and Bi ( NO 3)3 (C) AgNO 3 and Bi ( NO 3)3 (D) Pb ( NO 3)2 and Hg ( NO 3)2

Tardigrade Admin · Accepted Answer

Pb ( OH )2, Zn ( OH )2 and Bi ( OH )3 are white precipitates but Hg ( OH )2 (unstable) is not. PbCl 2 is white ppt. So, option (A), (B) and (C) are correct.

$P b (N O_{3})_{2}$ and $Z n (N O_{3})_{2}$

$P b (N O_{3})_{2}$ and $B i (N O_{3})_{3}$

$A g N O_{3}$ and $B i (N O_{3})_{3}$

$P b (N O_{3})_{2}$ and $H g (N O_{3})_{2}$

$P b (O H)_{2}, Z n (O H)_{2}$ and $B i (O H)_{3}$ are white precipitates but $H g (O H)_{2}$ (unstable) is not. $P b C l_{2}$ is white $ppt$ .
So, option (A), (B) and (C) are correct.

Q. A mixture of two salts is used to prepare a solution S, which gives the following results: White precipitate(s) onlyDiluteNaOH(aq)Room temperature​(aq solution of the salts)S​Dilute HCl(aq)Room temperature​ White precipitate(s) only The correct option(s) for the salt mixture is(are)

Pb(NO3​)2​ and Zn(NO3​)2​

Pb(NO3​)2​ and Bi(NO3​)3​

AgNO3​ and Bi(NO3​)3​

Pb(NO3​)2​ and Hg(NO3​)2​

Pb(OH)2​,Zn(OH)2​ and Bi(OH)3​ are white precipitates but Hg(OH)2​ (unstable) is not. PbCl2​ is white ppt. So, option (A), (B) and (C) are correct.

$P b (N O_{3})_{2}$ and $Z n (N O_{3})_{2}$

$P b (N O_{3})_{2}$ and $B i (N O_{3})_{3}$

$A g N O_{3}$ and $B i (N O_{3})_{3}$

$P b (N O_{3})_{2}$ and $H g (N O_{3})_{2}$

$P b (O H)_{2}, Z n (O H)_{2}$ and $B i (O H)_{3}$ are white precipitates but $H g (O H)_{2}$ (unstable) is not. $P b C l_{2}$ is white $ppt$ .
So, option (A), (B) and (C) are correct.