A mixture of two immiscible liquids A and B, having vapour pressure in pure state obeys the following relationship if chi A and chi B are mole fractions of A and B in vapour phase over the solution

Question

A mixture of two immiscible liquids A and B, having vapour pressure in pure state obeys the following relationship if chi A and chi B are mole fractions of A and B in vapour phase over the solution (A) P A prime= P M chi A prime (B) (P A prime/P B prime)=(W A × M w B /M wA × W B ) (C) If P A prime>P B prime then chi A prime< chi B prime (D) If P A prime>P B prime then n A >n B

Tardigrade Admin · Accepted Answer

For immiscible liquids P A prime=P M ⋅ chi A prime ; P B prime=P M ⋅ chi B prime ∴ (P A prime/P B prime)=( chi A prime/ chi B prime)=(n A /n B )=(W A × M w B /M w A × W B ) If PA prime> P B prime, then n A >n B

Q. A mixture of two immiscible liquids $A$ and $B$ , having vapour pressure in pure state obeys the following relationship if $χ_{A}$ and $χ_{B}$ are mole fractions of $A$ and $B$ in vapour phase over the solution

$P_{A}^{'} = P_{M} χ_{A}^{'}$

$\frac{P _{A}^{'}}{P _{B}^{'}} = \frac{W _{A} \times M w _{B}}{M w _{A} \times W _{B}}$

If $P_{A}^{'} > P_{B}^{'}$ then $χ_{A}^{'} < χ_{B}^{'}$

If $P_{A}^{'} > P_{B}^{'}$ then $n_{A} > n_{B}$

For immiscible liquids
$P_{A}^{'} = P_{M} \cdot χ_{A}^{'}; P_{B}^{'} = P_{M} \cdot χ_{B}^{'}$
$∴ \frac{P _{A}^{'}}{P _{B}^{'}} = \frac{χ _{A}^{'}}{χ _{B}^{'}} = \frac{n _{A}}{n _{B}} = \frac{W _{A} \times M w _{B}}{M w _{A} \times W _{B}}$
If $P_{A}^{'} > P_{B}^{'}$ , then $n_{A} > n_{B}$

Q. A mixture of two immiscible liquids A and B, having vapour pressure in pure state obeys the following relationship if χA​ and χB​ are mole fractions of A and B in vapour phase over the solution

PA′​=PM​χA′​

PB′​PA′​​=MwA​×WB​WA​×MwB​​

If PA′​>PB′​ then χA′​<χB′​

If PA′​>PB′​ then nA​>nB​