A mixture of NO2 and N2O4 has a vapour density of 38.3 at 300 K. What is the number of moles of NO2 in 100 g of the mixture?

Question

A mixture of NO2 and N2O4 has a vapour density of 38.3 at 300 K. What is the number of moles of NO2 in 100 g of the mixture? (A) 0.043 (B) 4.4 (C) 3.4 (D) 0.437

Tardigrade Admin · Accepted Answer

No. of molecules = 2 × V.d 2 × 38.3 = 76.6 Weight of NO2 =x So that weight of N2O4=100-x Hence, (x/46)+(100-x/92)=(100/76.6) =(2x+100-x/92)=(100/76.6) x = 20.10, the number of moles of NO2 =(20.10/46)=0.437

Q. A mixture of $N O_{2}$ and $N_{2} O_{4}$ has a vapour density of $38.3$ at $300 K$ . What is the number of moles of $N O_{2}$ in $100 g$ of the mixture?

$0.043$

$4.4$

$3.4$

$0.437$

Q. A mixture of NO2​ and N2​O4​ has a vapour density of 38.3 at 300K. What is the number of moles of NO2​ in 100g of the mixture?

0.043

4.4

3.4

0.437

No. of molecules =2×V.d 2×38.3=76.6 Weight of NO2​=x So that weight of N2​O4​=100−x Hence, 46x​+92100−x​=76.6100​ =922x+100−x​=76.6100​ x=20.10, the number of moles of NO2​ =4620.10​=0.437

Q. A mixture of $N O_{2}$ and $N_{2} O_{4}$ has a vapour density of $38.3$ at $300 K$ . What is the number of moles of $N O_{2}$ in $100 g$ of the mixture?

$0.043$

$4.4$

$3.4$

$0.437$